Answer
0.0409.
Work Step by Step
By using the Central Limit Theorem, the sample mean has a mean of $\mu$ and standard deviation of $\frac{\sigma}{\sqrt n}$. $z=\frac{value-mean}{standard \ deviation}=\frac{4.444-4.457}{\frac{0.382}{\sqrt{25}}}=-1.74.$ Using the table, the probability of z being less than -0.52 is: 0.0409.
