## Elementary Statistics (12th Edition)

a)$z=\frac{value-mean}{standard \ deviation}=\frac{72-69.5}{2.4}=1.04.$ Using the table, the probability of z being less than 1.04 is: 0.8508=85.08%. Hence the height doesn't seem to be good, because for almost 15% of men it would be small. b)By using the table, the z-score corresponding to 99%=0.99: z=2.33. Hence the corresponding value:$mean+z⋅standard \ deviation=69.5+2.33⋅2.4=75.092.$