Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 6 - Normal Probability Distributions - 6-3 Applications of Normal Distributions - Basic Skills and Concepts: 7

Answer

0.9053.

Work Step by Step

$z_1=\frac{value-mean}{standard \ deviation}=\frac{133-100}{15}=2.2.$ $z_2=\frac{value-mean}{standard \ deviation}=\frac{79-100}{15}=-1.4.$ Using the table, the value belonging to 2.2: 0.9861, the table, the value belonging to -1.4: 0.0808. 0.9861-0.0808=0.9053.
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