Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 4 - Probability - Review - Review Exercises: 7

Answer

a)$\frac{1}{575757}$ b)$\frac{1}{19}$ c)$\frac{1}{10,939,383}$

Work Step by Step

a) Because the order is not important, we can use the combination rule to determine the number of possibilities: $\frac{39!}{(39-5)!5!}=575757.$ We also know that $probability=\frac{number \ of \ good \ outcomes}{number\ of\ all\ outcomes}$, therefore $P=\frac{1}{575757}$. b) We know that $probability=\frac{number \ of \ good \ outcomes}{number\ of\ all\ outcomes}$, therefore $P=\frac{1}{19}$. c) Then for the probability of winning the jackpot we can use the multiplication rule: P=$\frac{1}{575757}\cdot \frac{1}{19}=\frac{1}{10,939,383}$
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