Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 4 - Probability - 4-6 Counting - Basic Skills and Concepts: 21

Answer

a) 11880 b)495 c) $\frac{1}{495}$

Work Step by Step

a) Because the order is important, we can use the permutation rule to determine the number of possibilities: $\frac{12!}{(12-4)!}=11880.$ b)Because the order is not important, we can use the combination rule to determine the number of possibilities: $\frac{12!}{(12-4)!4!}=495.$ c) By using the properties of b), and we also know that $probability=\frac{number \ of \ good \ outcomes}{number\ of\ all\ outcomes}$, therefore $P=\frac{1}{495}$.
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