Answer
Variance:$82.62 \ (\$)^2$.
Standard deviation:$9.09 \$$
Range:$22.85\$$.
Work Step by Step
By using the results from before: $\mu=59.22 \ \$.$
Variance=$\frac{\sum (x-\mu)^2}{n}=\frac{(55.99-59.22)^2+(69.99-59.22)^2+...+(59.68-59.22)^2}{6}=82.62 \ (\$)^2.$
Standard deviation=$\sqrt{variance}=\sqrt{82.62 \ (\$)^2}=9.09 \$$
Range=maximum value-minimum value=$71.77 \$-48.92 \$=22.85\$$.
