Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 10 - Correlation and Regression - 10-2 Correlation - Beyond the Basics: 34

Answer

±0.445063.

Work Step by Step

The critical value t using the table with $\alpha=0.02$ and df=27-2=25: $t=\pm 2.485$. Hence, by using the given formula I determine the critival r-values: $r=\frac{\pm t}{\sqrt{t^2+n-2}}=\frac{\pm 2.485}{2.485^2+27-2}=\pm 0.445063.$
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