Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 10 - Correlation and Regression - 10-2 Correlation - Basic Skills and Concepts - Page 512: 10

Answer

a. The scatter diagram can be constructed by hand or using a software. b. the value of r is 0.816286739. This is evidence that there exists a correlation between x and y. c. The outlier.

Work Step by Step

Step 1 We calculate the linear correlation coefficient which will help us to make a decision on whether there is a linear correlation or not. We use the formula: $r= \frac{n(∑xy)-(∑x)(∑y)} {\sqrt{n(∑x^2 )-(∑x)^2 } \sqrt{n(∑y^2 )-(∑y)^2 }} $ Step 2 We find the statistics as follows: $∑x=99$ $∑y=82.5$ $∑xy=797.47$ $∑x^2 =1001$ $∑y^2 =659.9762$ Step 3 Replace the statistics in the formula with their respective values. $r= \frac{(11*797.47)-(99)(82.5)} {\sqrt{11(1001)-99^2 } \sqrt{11(659.976)-82.5^2 }}$ Step 4 The value of r is $r=0.816286739$ Step 5 We conclude that there is a linear correlation between x and y since the value of r is closer to 1.
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