Applied Statistics and Probability for Engineers, 6th Edition

Published by Wiley
ISBN 10: 1118539710
ISBN 13: 978-1-11853-971-2

Chapter 3 - Section 3-2 - Probability Distributions and Probability Mass Functions - Exercises - Page 69: 3-21

Answer

(a) P(X≥2)=0.3 (b) P(X<1.65)=0.6 (c) P(X=1.5) = 0.4 (d) P(X<1.3)or=X>21)=0.2

Work Step by Step

Given that, f(1.25)=0.2,f(1.5)=0.4,f(1.75)=0.1,f(2)=0.2,f(2.25)=0.1, this means that for all possible values of x, f(x) ≥ 0, and, P(X=1.25)+P(X=1.5)+P(X=1.75)+P(X=2)+P(X=2.25)=0.2+0.4+0.1+0.2+0.1=1 (a) P(X≥2)=P(X=2)+P(X=2.25) = 0.2+0.1=0.3 (b) P(X<1.65)=P(X=1.25)+P(X=1.5) = 0.2+0.4=0.6 (c) P(X=1.5) = 0.4 (d) P(X<1.3)or=X>21)=P(X=1.25)= 0.2
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.