Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 7 - Section 7.1 - Trigonometric Identities - 7.1 Exercises - Page 543: 9

Answer

$\sin u+\cot u\cos u=\csc u$

Work Step by Step

$\sin u+\cot u\cos u$ Substitute $\cot u$ with $\dfrac{\cos u}{\sin u}$ and simplify: $\sin u+(\dfrac{\cos u}{\sin u})(\cos u)=\sin u+\dfrac{\cos^{2}u}{\sin u}=...$ $...=\dfrac{\sin^{2}u+\cos^{2}u}{\sin u}=...$ Since $\sin^{2}u+\cos^{2}u=1$, this expression becomes: $...=\dfrac{1}{\sin u}=\csc u$
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