Answer
a) Refer to image
b) 5$\sqrt 5$
c) (4.5, -6)
d) y=2x-15
e) 125= ($x-7)^{2}$ + ($y+1)^{2}$
Work Step by Step
b) Use Pythagorean theorem to find the distance between P and Q
c) Divide triangle dimensions in half and then subtract those values from the coordinates of P... (7-2.5, -1-5)
d) Use the triangle dimensions of 10 and 5 to find the slope, which is 2. Then plug that into the equation and simplify
e) Use the equation for a circle... $r^{2}$= $(x-h)^{2}$ + $(y-k)^{2}$... and the coordinates of P and the radius to fill in the equation. R stands for radius and h and k are used for point P
