Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Section 4.2 One-to-One Functions; Inverse Functions - 4.2 Assess Your Understanding - Page 294: 105

Answer

$6xh+3h^2-7h$

Work Step by Step

Given $f(x)=3x^2-7x$, we have $f(x+h)-f(x)=3(x+h)^2-7(x+h)-(3x^2-7x)=6xh+3h^2-7h$
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