Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - Test: 6

Answer

$\color{blue}{-4}$

Work Step by Step

Substitute the given values of the variables to obtain: $=\left|\dfrac{(-2)^2+2(-4)(5)}{3(-2+5)}\right| \\=\dfrac{4+(-40)}{3(3)} \\=\dfrac{-36}{9}$ Simplify the fraction by cancelling out the common factors to obtain: $\require{cancel} \\=\dfrac{\cancel{-36}(-4)}{\cancel{(9)}} \\=\color{blue}{-4}$
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