Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.3 Polynomials - R.3 Exercises: 30

Answer

$\frac{p^{8}}{q^2}$.

Work Step by Step

The rule $(\frac{a}{b})^n = \frac{a^n}{b^n}$. $(\frac{p^4}{q^1})^2 = \frac{p^{4\times2}}{q^{1\times2}} = \frac{p^{8}}{q^2}$.
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