Chapter R - Review of Basic Concepts - R.2 Real Numbers and Their Properties - R.2 Exercises - Page 22: 117

$0.031$

Body-wt in lb $=190$ hr of drinking $=2$ Number of oz $=48$ % alcohol $=3.2$ The formula is $\text{BAC } = 48 \times 3.2 \times 0.075 \div 190 - 2 \times 0.015$ $\text{BAC } = \dfrac{48 \times 3.2 \times 0.075}{190}- 2\times 0.015$ $\text{BAC } = \dfrac{11.52}{190}-0.03$ $\text{BAC } \approx 0.031$