Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.2 Real Numbers and Their Properties - R.2 Exercises: 102

Answer

true

Work Step by Step

RECALL: The absolute value of a number $a$ is defined as: $|a| = a$ if $a \ge 0$ $|a| = -a$ if $a \lt 0$ Thus, $|11| \cdot |-6| = 11 \cdot [-(-6)] = 11 \cdot 6 66$ while $|-66| = -(-66) = 66$ Therefore, $|11| \cdot |-6| = |-66|$ The statement is true.
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