Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 8 - Application of Trigonometry - 8.4 Algebraically Defined Vectors and the Dot Product - 8.4 Exercises - Page 791: 63

Answer

$\bf{Orthogonal}$

Work Step by Step

When the dot product of two vectors becomes zero, the vectors are said to be orthogonal, for this we will multiply the corresponding components together and then adding . In general, we have the formula as: $ \lt a , b\gt \cdot \lt c, d \gt =ac+bd$ We have: $a=\lt 1, 2 \gt $ and $b = \lt -6, 3 \gt $ Now, $a \cdot b=\lt 1, 2 \gt \cdot \lt -6, 3 \gt =(1)(-6)+(2)(3)=-6+6=0 $ Therefore, the two vectors are $\bf{Orthogonal}$ .
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