Answer
$\angle a=37.2°$
$A=178.39m$
$C=244.33m$
Work Step by Step
Sum of internal angles of triangle is $180°$ then:
$\angle a+\angle b+\angle c=180°$
$\angle a=180°-\angle b-\angle c$
$\angle a=180°-18.7°-124.1°$
$\angle a=37.2°$
By using the sine of laws we have:
$$\frac{A}{\sin{a}}=\frac{B}{\sin{b}}=\frac{C}{\sin{c}}$$
Solving for $A$ we have:
$$A=\frac{B\sin{a}}{\sin{b}}=\frac{94.6\sin{(37.2)°=}}{\sin{(18.7°)}}$$
$$A=178.39°$$
Solving for $C$ we have:
$$C=\frac{B\sin{a}}{\sin{b}}=\frac{94.6\sin{(124.1°)}}{\sin{(18.7°)}}$$
$$C=244.33°$$
