Chapter 7 - Trigonometric Identities and Equations - 7.4 Double-Angle and Half-Angle Identities - 7.4 Exercises - Page 693: 30

$=\dfrac {1}{16}\sin 59^{0}$

$2\sin \alpha \cos \alpha =\sin 2\alpha \Rightarrow \dfrac {1}{8}\sin 29.5\cos 29.5=\dfrac {1}{16}\left( 2\sin 29.5\cos 29.5\right) =\dfrac {1}{16}\sin (2\times 29.5=\dfrac {1}{16}\sin 59^{0}$