Answer
$e^{1/2}=\sqrt e$
Work Step by Step
Since $log_bx=y \rightarrow b^y=x$, we have $ln\sqrt e=\frac{1}{2} \rightarrow e^{1/2}=\sqrt e$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 4 - Inverse, Exponential, and Logarithmic Functions - Chapter 4 Test Prep - Review Exercises - Page 491: 23
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