Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.4 Evaluation Logarithms and the Change-of-Base Theorem - 4.4 Exercises - Page 458: 66

Answer

$1,258,900,000I_0$

Work Step by Step

Following the definition of Richter scale ratings, we have: $ log(\frac{I}{I_0})=9.1$ thus $\frac{I}{I_0}=10^{9.1}$ and $I=10^{9.1}I_0\approx1,258,900,000I_0$
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