Answer
$f(x)=(\frac{1}{6})^x$
Work Step by Step
For $f(x)=a^x$ to contain point $(-2,36)$, we have $f(-2)=a^{-2}=36$ which gives $a=\frac{1}{6}$, thus $f(x)=(\frac{1}{6})^x$
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