Answer
See graph.
Work Step by Step
Step 1. Given $f(x)=2x^3+x^2-x=x(x+1)(2x-1)$, we can find its zeros as $x=-1,0,1/2$, y-intercept $f(0)=0$. Function is neither even nor odd. End behavior: rise to the right and fall to the left. Maximum number of turning points $2$.
Step 2. Use the information above and test point to graph the function as shown in the figure.