Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 3 - Polynomial and Rational Functions - 3.4 Polynomial Functions: Graphs, Applications, and Models - 3.4 Exercises - Page 353: 66

Answer

$f(x)=\frac{1}{5}(x+5)(x-3)^2$

Work Step by Step

Step 1. Identify zeros from the graph: $x=-5,3,3$ Step 2. Write a form of the polynomial: $f(x)=k(x+5)(x-3)(x-3)$ where $k$ is unknown. Step 3. As point $(0,9)$ is on the curve, we have $f(0)=k(0+5)(0-3)(0-3)=9$, thus $k=\frac{1}{5}$ Step 4. $f(x)=\frac{1}{5}(x+5)(x-3)^2$
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