Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 3 - Polynomial and Rational Functions - 3.3 Zeros of Polynomial Functions - 3.3 Exercises - Page 335: 2

Answer

True.

Work Step by Step

True. Based on the Remainder theorem, $f(1)=0$ means that the remainder of the division $f(x)/(x-1)$ is zero, thus $(x-1)$ is a factor of $f(x)$
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