Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.6 Graphs of Basic Functions - 2.6 Exercises - Page 256: 24

Answer

$8$

Work Step by Step

Step 1. From the given equation, we have $(x-5)^2+(y-12)^2=25$, thus we can identify the center of the circle as $(5,12)$ and radius $r=5$ Step 2. The distance from the origin to this center is $d=\sqrt {5^2+12^2}=13$ Step 3. The shortest distance from the origin to the circle is the on the line connecting the origin to the center of the circle, and can be found as $d_m=d-r=8$
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