## Precalculus (6th Edition)

Published by Pearson

# Chapter 2 - Graphs and Functions - 2.4 Linear Functions - 2.4 Exercises: 63

#### Answer

Refer to the graph below.

#### Work Step by Step

Plot the point $(-\frac{5}{2}, 3)$. Use the slope to plot another point. A line with an undefined slope is vertical. All points on a vertical line share the same x-coordinate. Since $(-\frac{5}{2}, 3)$ is on the line, then the point $(-\frac{5}{2}, -3)$ must also be on the line. Plot $(-\frac{5}{2}, -3)$. Complete the graph by using a line to connect the two points. (Refer to the graph in the answer part above.)

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