Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.4 Quadratic Equations - 1.4 Exercises: 68

Answer

$x = 3$

Work Step by Step

$x^3 - 27 = 0$ $x^3 - 27 + 27 = 27 $ $x ^3 = 27 $ $\sqrt[3] {x^3} = \sqrt[3] {27}$ $x = 3$
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