Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.4 Quadratic Equations - 1.4 Exercises: 22

Answer

The solution is $x = \frac{2}{3}$

Work Step by Step

$9x^2 - 12x + 14 = (3x - 2)^2= 0$ $3x - 2= 0$ $3x =2$ $x = \frac{2}{3}$ OR $3x - 2= 0$ $3x =2$ $x = \frac{2}{3}$ The solution is $x = \frac{2}{3}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.