Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.9 - Linear Inequalities and Absolute Value Inequalities - Exercise Set - Page 140: 145

Answer

See below:

Work Step by Step

Consider the equation $y=\left| x+1 \right|$. Substitute $x=-4$ and solve: $\begin{align} & y=\left| x+1 \right| \\ & =\left| -4+1 \right| \\ & =\left| -3 \right| \\ & =3 \end{align}$ Substitute $x=-3$ and solve: $\begin{align} & y=\left| x+1 \right| \\ & =\left| -3+1 \right| \\ & =\left| -2 \right| \\ & =2 \end{align}$ Substitute $x=-2$ and solve: $\begin{align} & y=\left| x+1 \right| \\ & =\left| -2+1 \right| \\ & =\left| -1 \right| \\ & =1 \end{align}$ Substitute $x=-1$ and solve: $\begin{align} & y=\left| x+1 \right| \\ & =\left| -1+1 \right| \\ & =\left| 0 \right| \\ & =0 \end{align}$ Substitute $x=0$ and solve: $\begin{align} & y=\left| x+1 \right| \\ & =\left| 0+1 \right| \\ & =\left| 1 \right| \\ & =1 \end{align}$ Substitute $x=1$ and solve: $\begin{align} & y=\left| x+1 \right| \\ & =\left| 1+1 \right| \\ & =\left| 2 \right| \\ & =2 \end{align}$ Substitute $x=2$ and solve: $\begin{align} & y=\left| x+1 \right| \\ & =\left| 2+1 \right| \\ & =\left| 3 \right| \\ & =3 \end{align}$
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