Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Review Exercises: 27

Answer

$\frac{1}{27}$

Work Step by Step

Expand the exponents in the numerator and denominator, and simplify: $$\frac{3^3}{3^6}=\frac{3\cdot 3\cdot 3}{3\cdot 3\cdot 3\cdot3\cdot 3\cdot 3}=\frac{1}{3\cdot 3\cdot 3}=\frac{1}{27}$$
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