Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 9 - Section 9.3 - Area, Volume, and Surface Area - Practice - Page 630: 6

Answer

$V = \frac{11}{21}$ cubic cm

Work Step by Step

$V = \frac{4}{3} \pi r^{3}$ $V = \frac{4}{3} \times \frac{22}{7} \times \frac{1}{2}^{3}$ $V = \frac{88}{21} \times \frac{1}{8}$ $V = \frac{88}{168}$ $V = \frac{11}{21}$
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