Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 9 - Section 9.2 - Perimeter - Exercise Set: 60

Answer

$4^{1}$ $\times$ ($2^{3}$ - 8 ) = 0

Work Step by Step

$4^{1}$ $\times$ ($2^{3}$ - 8 ) = 4 $\times$ (8 - 8) = (Work inside the parenthesis first ) 4 $\times$ 0 = 0
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