## Prealgebra (7th Edition)

$4^{1}$ $\times$ ($2^{3}$ - 8 ) = 0
$4^{1}$ $\times$ ($2^{3}$ - 8 ) = 4 $\times$ (8 - 8) = (Work inside the parenthesis first ) 4 $\times$ 0 = 0