Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 9 - Review - Page 691: 117

Answer

$346\frac{1}{2}$ $in^3$

Work Step by Step

The formula for the volume of a cone is: $V$ $=$ $π$$r^2$$\frac{h}{3}$ The problem says to use $\frac{22}{7}$ as an approximation for pi. So, lets fill in the formula with the correct numbers. $π$ $=$ $\frac{22}{7}$ $r$ $=$ $5$$\frac{1}{4}$ $h$ $=$ $12$ $V$ $=$ $\frac{22}{7}$ $\times$ ($5\frac{1}{4}$)$^2$ $\times$ $\frac{12}{3}$ $V$ $=$ $\frac{22}{7}$ $\times$ $\frac{441}{16}$ $\times$ $4$ $V$ $=$ $346.5$ or $346\frac{1}{2}$ $346\frac{1}{2}$ $in^3$
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