Answer
a) $-$$\frac{1}{27}$
b) $\frac{9}{49}$
Work Step by Step
Use the exponent power of a fraction rule to solve this problem: ($\frac{a}{b}$)$^{x}$ $=$ $\frac{a^{x}}{b^x}$
For problem a, raise both the numerator and denominator to the 3rd power:
$-$ $\frac{(1^3)}{(3^3)}$ $=$ $-$ $\frac{1}{27}$
For problem b, raise both the numerator and denominator to the 2nd power:
$\frac{(3^2)}{(7^2)}$ $=$ $\frac{9}{49}$
