Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 6 - Section 6.2 - Integrated Review - Ratio, Rate, and Proportion - Page 430: 33

Answer

False/Not true

Work Step by Step

First, multiply by 4 on both sides to get rid of the 4 in the denominator on the left: $\frac{7}{4}\cdot 4 = \frac{5}{3}\cdot 4 \rightarrow 7 = \frac{20}{3}$ Then, multiply by 3 on both sides to get rid of the 3 in the denominator on the right: $7\cdot 3 = \frac{20}{3}\cdot 3 \rightarrow 21 = 20$ 20 does not equal 21, so the proportion is not true.
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