Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Review: 84

Answer

$-\frac{1}{27}$

Work Step by Step

$\frac{2}{27}-(\frac{1}{3})^2\ \longrightarrow$ evaluate exponent =$\frac{2}{27}-\frac{1}{9}\ \longrightarrow$convert to like fractions =$\frac{2}{27}-\frac{1\times3}{9\times3}\ \longrightarrow$LCD is 27 =$\frac{2}{27}-\frac{3}{27}\ \longrightarrow$subtract =$\frac{-1}{27}$
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