Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 10 - Review - Page 728: 51

Answer

$z^2+z+4$

Work Step by Step

$\begin{aligned}(z^2-5z+8)+(6z-4)&=z^2-5z+8+6z-4\text{ [Remove parentheses]}\\&=z^2+(-5z+6z)+(8-4) \text{[Group like terms]}\\&=z^2+z+4\end{aligned}$
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