Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 10 - Review: 22

Answer

$6x^{30}y^{25}$

Work Step by Step

$(3x^6y^5)^3(2x^6y^5)^2=(3x^{6\times3}y^{5\times3})(2x^{6\times2}y^{5\times2})=(3x^{18}y^{15})(2x^{12}y^{10})=6x^{18+12}y^{15+10}=6x^{30}y^{25}$
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