Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 10 - Review: 7

Answer

$-11y^2-y+\frac{3}{4}$

Work Step by Step

Subtract $9y^2$ from $-20y^2$ to get $-11y^2$ Subtract y. So far you have $-11y^2-y$ Add $\frac{1}{2}$ and $\frac{1}{4}$. The $-\frac{1}{4}$ becomes positive because the two negative signs cancel out. Result: $-11y^2-y+\frac{3}{4}$
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