Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 1 - Section 1.7 - Exponents and Order of Operations - Practice: 13

Answer

7

Work Step by Step

$\frac{25+8\times2-3^{3}}{2\times(3-2)}$=$\frac{25+8\times2-3^{3}}{2\times1}$=$\frac{25+8\times2-27}{2\times1}$=$\frac{25+16-27}{2}$=$\frac{41-27}{2}$=$\frac{14}{2}$=7
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