Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Appendix B - Practice - Page 740: 10

Answer

$\frac{7}{12}$

Work Step by Step

Given: $4^{-1}+3^{-1}$ To simplify this, recall that when n is raised to -1, it will have a value equivalent to $ \frac{1}{n}$. So we will convert the values to fraction $\frac{1}{4}+\frac{1}{3}$ Since they both have different denominator, we will use 12 which is the least common denominator of 4 and 3 and simplify =$\frac{4}{12}+\frac{3}{12}$ =$\frac{7}{12}$
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