Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 9 - Measurement - 9.1 Measuring Length; The Metric System - Exercise Set 9.1 - Page 584: 30

Answer

$\approx 10 \text{ in.}$

Work Step by Step

Convert by multiplying $\dfrac{1 \text{ in.}}{2.54 \text{ cm}}$ to obtain: $\require{cancel}=26 \cancel{\text{ cm}}\cdot \dfrac{1 \text{ in.}}{2.54 \cancel{\text{ .cm}}} \\=\dfrac{26}{2.54} \text{ in.} \\=10.23622047 \text { in.} \\\approx 10 \text{ in.}$
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