Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 6 - Algebra: Equations and Inequalities - Chapter 6 Test - Page 406: 9

Answer

\[x=\frac{15}{2}\]

Work Step by Step

Consider the equation \[\frac{5}{8}=\frac{x}{12}\] The LCM of both the denominators of the above equation is 24 so multiply by 24 on both the sides of the equation \[\begin{align} & \frac{5}{8}\times 24=\frac{x}{12}\times 24 \\ & 15=2x \end{align}\] Divide both the sides by 2 \[x=\frac{15}{2}\] Now, to check it, put \[x=\frac{15}{2}\]in the equation \[\begin{align} & \frac{5}{8}=\frac{x}{12} \\ & \frac{5}{8}=\frac{15}{2\times 12} \\ & \frac{5}{8}=\frac{15}{24} \\ & \frac{5}{8}=\frac{5}{8} \end{align}\] which is true. Hence, required solution is\[x=\frac{15}{2}\].
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