## Thinking Mathematically (6th Edition)

Published by Pearson

# Chapter 6 - Algebra: Equations and Inequalities - 6.5 Quadratic Equations - Concept and Vocabulary Check: 6

(4x+1)(2x-3)

#### Work Step by Step

$8x^{2}$ - 10x -3 = (4x+1) (2x__) step 1. Find two first terms whose product is $8x^{2}$ $8x^{2}$ - 10x -3 = (4x+1) (2x__) which is given and Step 2. To find the second term of each factor, we must find two integers whose product is -3 and whose sum is -10 List pairs of factors of the constant, -3 (1,-3)(-1,3) step 3. The correct factorization of $8x^{2}$ - 10x -3 is the one in which the sum of the Outside and Inside products is equal to -10x. list of the possible factorization : (4x-1)(2x+3) = $8x^{2}$ +10x -3 (4x+1)(2x-3) =$8x^{2}$ - 10x -3 So, (4x+1)(2x-3) is the solution

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