Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 4 - Number Representation and Calculation - 4.2 Number Bases in Positional Systems - Exercise Set 4.2 - Page 227: 79

Answer

$11111011_2\lt673_8\lt3A6_{12}$

Work Step by Step

$11111011_2=1\cdot1+1\cdot2+0\cdot4+1\cdot8+1\cdot16+1\cdot32+1\cdot64+1\cdot128=1+2+8+16+32+64+128=251$ $3A6_{12}=6\cdot1+10\cdot12+3\cdot144=6+120+432=558$ $673_8=3\cdot1+7\cdot8+6\cdot64=3+56+384=443$. Thus the order is: $11111011_2\lt673_8\lt3A6_{12}$
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