Answer
The argument is invalid and its symbolic form is:
\[\begin{align}
& p\to q \\
& \frac{\text{ }q}{\therefore \text{ }p} \\
\end{align}\]
Thinking Mathematically (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0321867327
ISBN 13:
978-0-32186-732-2
Chapter 3 - Logic - 3.7 Arguments and Truth Tables - Exercise Set 3.7 - Page 192: 52
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