Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 12 - Statistics - 12.2 Measures of Central Tendency - Exercise Set 12.2 - Page 792: 52

Answer

See below.

Work Step by Step

The midrange is the sum of the minimum and maximum data value divided by $2$. The mode of $n$ numbers is the number or numbers that appear(s) most frequently. If all items appear the same number of times, then there is no mode. The median of $n$ numbers is the middle number of the numbers when they are in order (and the mean of the middle $2$ numbers if $n$ is even). The mean of $n$ numbers is the sum of the numbers divided by $n$. Here we have $16$ items (obtained by summing the numbers in the right column), thus the mean will be the mean of the $8$th and $9$th item, which according to the table is: $(13+13)/2=13$. Here the midrange: $\frac{10+15}{2}=12.5$, the mode: $13$ and the mean: $\frac{1\cdot10+2\cdot11+4\cdot12+5\cdot13+2\cdot14+2\cdot15}{16}\approx12.69$.
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