Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - 11.7 Events Involving And; Conditional Probability - Exercise Set 11.7: 29

Answer

0.008

Work Step by Step

If A, and B are independent events, then P(E) = P(A)*P(B) a.) What are the chances that three randomly selected cigarette smokers suffer from hangovers? A: frequent hangovers B: frequent hangovers C: frequent hangovers P(A) = 0.20 P(B) =0.20 P(C)= 0.20 P(E) = P(A)*P(B)*P(C) P(E) =0.20 x 0.20 x 0.20 =0.008
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