Discrete Mathematics with Applications 4th Edition

Published by Cengage Learning
ISBN 10: 0-49539-132-8
ISBN 13: 978-0-49539-132-6

Chapter 9 - Counting and Probability - Exercise Set 9.7 - Page 603: 4

Answer

$\frac{n(n-1)(n-2)}{6}$

Work Step by Step

The expression is $\frac{n!}{3!(n-3)!}$, which is $\frac{n(n-1)(n-2)}{3!}$=$\frac{n(n-1)(n-2)}{6}$
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